-4p+p^2=-13.2p-5p^2=7

Solution for -4p+p^2=-13.2p-5p^2=7 equation:

-4p+p^2=-13.2p-5p^2=7

We move all terms to the left:

-4p+p^2-(-13.2p-5p^2)=0

We get rid of parentheses

p^2+5p^2+13.2p-4p=0

We add all the numbers together, and all the variables

6p^2+9.2p=0

a = 6; b = 9.2; c = 0;
Δ = b2-4ac
Δ = 9.22-4·6·0
Δ = 84.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.2)-\sqrt{84.64}}{2*6}=\frac{-9.2-\sqrt{84.64}}{12}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.2)+\sqrt{84.64}}{2*6}=\frac{-9.2+\sqrt{84.64}}{12}
$